2024年最新の100%試験高合格率1z1-829問題集PDF
合格させる試験完全版1z1-829問題集50解答
質問 # 10
Given the code fragment:
What is the result?
- A. Dog
Dog - B. Cat
null - C. Cat
Dog - D. A NullPointerException is thrown
Cat
Cat
正解：B
解説：
The answer is E because the code fragment creates a new Pet object with the name "Dog" and assigns it to the variable p. Then, it assigns p to p1. Next, it changes the name of p1 to "Cat". Then, it assigns p1 to p. Finally, it sets p to null and prints the name of p and p1. The output will be "Cat" and "null" because p is set to null and p1 still points to the Pet object with the name "Cat".
質問 # 11
Given the code fragment:
What is the result?
- A. PT5SPTIMP6D
- B. $SIM6D
- C. 5000$60M6D
- D. PT5000PT60MP6D
正解：D
解説：
The code fragment is creating a Duration object with a value of 5000 milliseconds, then printing it. Then, it is creating another Duration object with a value of 60 seconds, then printing it. Finally, it is creating a Period object with a value of 6 days, then printing it. The output will be "PT5000PT60MP6D". Reference: https://docs.oracle.com/javase/8/docs/api/java/time/Duration.html, https://docs.oracle.com/javase/8/docs/api/java/time/Period.html
質問 # 12
Given the code fragment:
What is the result?
- A. falase 0
true 1 - B. false 1
ture 2 - C. false 1
false 2 - D. true 1
false 2
正解：A
解説：
The code fragment is comparing the values of a, b, and c using the < and > operators. The first comparison, d, is checking if a is less than b and greater than c. Since a is equal to 2, b is equal to -2, and c is equal to -4, this comparison will evaluate to true. The second comparison, e, is checking if a is greater than b and a is greater than c. Since a is equal to 2, b is equal to -2, and c is equal to -4, this comparison will evaluate to false. Therefore, the result will be true 1 false 2. Reference: Operators (The Java™ Tutorials > Learning the Java Language - Oracle
質問 # 13
Given:
What is the result?
- A. Mb
MC - B. mA
- C. Mb
- D. Mb
- E. MA
正解：B
解説：
The code snippet is an example of Java SE 17 code. The code is checking if the object is an instance of class C and if it is, it will print "mC". If it is not an instance of class C, it will print "mA". In this case, the object is not an instance of class C, so the output will be "mA". Reference: Pattern Matching for instanceof - Oracle Help Center
質問 # 14
Which statement is true?
- A. IllegalStateException is thrown if a thread in waiting state is moved back to runnable.
- B. After the timed wait expires, the waited thread moves to the terminated state.
- C. A thread in waiting state must handle InterrupedException.
- D. thread in waiting state consumes CPU cycles.
正解：C
解説：
A thread in waiting state is waiting for another thread to perform a particular action, such as calling notify() or notifyAll() on a shared object, or terminating a joined thread. A thread in waiting state can be interrupted by another thread, which will cause the waiting thread to throw an InterruptedException and return to the runnable state. Therefore, a thread in waiting state must handle InterruptedException, either by catching it or declaring it in the throws clause. Reference: Thread.State (Java SE 17 & JDK 17), [Thread (Java SE 17 & JDK 17)]
質問 # 15
Given:
What is the result?
- A. Mb
MC - B. mA
- C. Mb
- D. Mb
- E. MA
正解：B
解説：
Explanation
The code snippet is an example of Java SE 17 code. The code is checking if the object is an instance of class C and if it is, it will print "mC". If it is not an instance of class C, it will print "mA". In this case, the object is not an instance of class C, so the output will be "mA". References: Pattern Matching for instanceof - Oracle Help Center
質問 # 16
Given the code fragment:
Which action enables the code to compile?
- A. Make the regNo variable public
- B. Replace record with void.
- C. Remove the regNO initialization statement.
- D. Replace thye regNo variable static
- E. Make the regNo variable static.
正解：A
解説：
The code will compile if the regNo variable is made public. This is because the regNo variable is being accessed in the main method of the App class, which is outside the scope of the Product class. Making the regNo variable public will allow it to be accessed from outside the class. Reference: https://education.oracle.com/products/trackp_OCPJSE17, https://mylearn.oracle.com/ou/learning-path/java-se-17-developer/99487, https://docs.oracle.com/javase/tutorial/java/javaOO/accesscontrol.html
質問 # 17
Given:
What is the result?
- A. Software Game Chess 2
- B. Software Game Software Game Chese 2
- C. Software Game read error
- D. Software game write error
- E. Software Game Software Game chess 0
- F. Software Game Chess 0
正解：B
解説：
Explanation
The answer is B because the code uses the writeObject and readObject methods of the ObjectOutputStream and ObjectInputStream classes to serialize and deserialize the Game object. These methods use the default serialization mechanism, which writes and reads the state of the object's fields, including the inherited ones. Therefore, the title field of the Software class is also serialized and deserialized along with the players field of the Game class. The toString method of the Game class calls the toString method of the Software class using super.toString(), which returns the value of the title field.
Hence, when the deserialized object is printed, it shows "Software Game Software Game Chess 2".
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Serialization and Deserialization in Java with Example
質問 # 18
Given:
What is the result?
- A. 1 RAINY
- B. 0 CLOUDY
- C. 1 Snowy
- D. 0 Snowy
- E. Compilation fails
正解：D
解説：
The code is defining an enum class called Forecast with three values: SUNNY, CLOUDY, and RAINY. The toString() method is overridden to always return "SNOWY". In the main method, the ordinal value of SUNNY is printed, which is 0, followed by the value of CLOUDY converted to uppercase, which is "CLOUDY". However, since the toString() method of Forecast returns "SNOWY" regardless of the actual value, the output will be "0 SNOWY". Reference: Enum (Java SE 17 & JDK 17), Enum.EnumDesc (Java SE 17 & JDK 17)
質問 # 19
Assuming that the data, txt file exists and has the following content:
Text1
Text2
Text3
Given the code fragment:
What is the result?
- A. text1-text2-text3
text3 - B. text1-
text2-
text3-
text3 - C. text1-text2-text3
text1
text2
text3 - D. text1-text2-text3
A java.lang.indexoutofBoundsException is thrown.
正解：A
解説：
Explanation
The answer is D because the code fragment reads the file "data.txt" and collects all the lines in the file into a single string, separated by hyphens. Then, it prints the resulting string. Next, it attempts to read the fourth line in the file (index 3) and print it. However, since the file only has three lines, an IndexOutOfBoundsException is thrown. References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Read contents of a file using Files class in Java
質問 # 20
Given the code fragments:
Which is true?
- A. The program prints t1 : 1: t2 : 1: t1 : t2 : 2 : in random order.
- B. The program prints t1 : 1: t2 : 1: t1 : 1 : t2 : 1 : indefinitely
- C. The program prints t1 : 1 : t2: 1 : t1 : 2 : t2: 2:
- D. The program prints an exception
正解：C
解説：
The code creates two threads, t1 and t2, and starts them. The threads will print their names and the value of the Atomic Integer object, x, which is initially set to 1. The threads will then increment the value of x and print their names and the new value of x. Since the threads are started at the same time, the output will be in random order. However, the final output will always be t1 : 1 : t2: 1 : t1 : 2 : t2: 2: Reference: AtomicInteger (Java SE 17 & JDK 17) - Oracle
質問 # 21
Given the code fragment:
What is the result?
- A. 0110
- B. True true false NewYear
- C. 010 optional (Newyear)
- D. False true true optional (Newyear)
正解：D
解説：
Explanation
The code fragment is using the stream methods allMatch, anyMatch, noneMatch, and findFirst on a list of strings called specialDays. These methods are used to perform matching operations on the elements of a stream, such as checking if all, any, or none of the elements satisfy a given predicate, or finding the first element that matches a predicate1. The predicate in this case is that the string equals "Labour" or
"Halloween". The output will be:
False: because not all of the elements in specialDays are equal to "Labour" or "Halloween".
true: because at least one of the elements in specialDays is equal to "Labour" or "Halloween".
true: because none of the elements in specialDays are equal to both "Labour" and "Halloween".
Optional[NewYear]: because the first element in specialDays that matches the predicate is "NewYear", and the findFirst method returns an Optional object that may or may not contain a non-null value2.
References: Stream (Java SE 17 & JDK 17), Optional (Java SE 17 & JDK 17)
質問 # 22
Given:
What is the result?
- A. The program throws a MissingResourceException.
- B. User name (EN - US)
- C. User name (US)
- D. User name (EN)
- E. UserName
正解：A
解説：
Explanation
The answer is B because the code fragment contains a logical error that causes a MissingResourceException at runtime. The code fragment tries to load a resource bundle with the base name "Captions.properties" and the locale "en_US". However, there is no such resource bundle available in the classpath. The available resource bundles are:
Captions.properties
Captions_en.properties
Captions_US.properties
Captions_en_US.properties
The ResourceBundle class follows a fallback mechanism to find the best matching resource bundle for a given locale. It first tries to find the resource bundle with the exact locale, then it tries to find the resource bundle with the same language and script, then it tries to find the resource bundle with the same language, and finally it tries to find the default resource bundle with no locale. If none of these resource bundles are found, it throws a MissingResourceException.
In this case, the code fragment is looking for a resource bundle with the base name "Captions.properties" and the locale "en_US". The ResourceBundle class will try to find the following resource bundles in order:
Captions.properties_en_US
Captions.properties_en
Captions.properties
However, none of these resource bundles exist in the classpath. Therefore, the ResourceBundle class will throw a MissingResourceException.
To fix this error, the code fragment should use the correct base name of the resource bundle family, which is
"Captions" without the ".properties" extension. For example:
ResourceBundle captions = ResourceBundle.getBundle("Captions", currentLocale); This will load the appropriate resource bundle for the current locale, which is "Captions_en_US.properties" in this case. References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
ResourceBundle (Java Platform SE 8 )
About the ResourceBundle Class (The Java™ Tutorials > Internationalization)
質問 # 23
Which two code fragments compile?
- A.
- B.
- C.
- D.
- E.
正解：A、E
解説：
Explanation
The two code fragments that compile are B and E. These are the only ones that use the correct syntax for declaring and initializing a var variable. The var keyword is a reserved type name that allows the compiler to infer the type of the variable based on the initializer expression. However, the var variable must have an initializer, and the initializer must not be null or a lambda expression. Therefore, option A is invalid because it does not have an initializer, option C is invalid because it has a null initializer, and option D is invalid because it has a lambda expression as an initializer. Option B is valid because it has a String initializer, and option E is valid because it has an int initializer.
https://docs.oracle.com/en/java/javase/17/language/local-variable-type-inference.html
質問 # 24
Given the content of the in. tart file:
23456789
and the code fragment:
What is the content of the out .txt file?
- A. 012345678901234
- B. 01234567801234
- C. 0123456789234567
- D. 0123456789
- E. 012345678
- F. 01234567
正解：D
解説：
The answer is D because the code fragment reads the content of the in.txt file and writes it to the out.txt file. The content of the in.txt file is "23456789". The code fragment uses a char array buffer of size 8 to read the content of the in.txt file. The while loop reads the content of the in.txt file and writes it to the out.txt file until the end of the file is reached. Therefore, the content of the out.txt file will be "0123456789".
質問 # 25
Given:
Which two should the module-info file include for it to represent the service provider interface?
- A. Provides.com.transport.vehicle.cars.Car with com.transport.vehicle.cars. impt, CatImpI;
- B. Exports com.transport.vehicle;
- C. exports com.transport.vehicle.cars.Car;
- D. Provides.com.transport.vehicle.cars.Car impl,CarImp1 to com.transport.vehicle.cars. Cars
- E. Exports com.transport.vehicle.cars;
- F. Requires cm.transport.vehicle,cars:
- G. Requires cm.transport.vehicle,cars:
正解：A、C
解説：
Explanation
The answer is B and E because the module-info file should include a provides directive and an exports directive to represent the service provider interface. The provides directive declares that the module provides an implementation of a service interface, which is com.transport.vehicle.cars.Car in this case. The with clause specifies the fully qualified name of the service provider class, which is com.transport.vehicle.cars.impl.CarImpl in this case. The exports directive declares that the module exports a package, which is com.transport.vehicle.cars in this case, to make it available to other modules. The package contains the service interface that other modules can use.
Option A is incorrect because requires is not the correct keyword to declare a service provider interface.
Requires declares that the module depends on another module, which is not the case here.
Option C is incorrect because it has a typo in the module name. It should be com.transport.vehicle.cars, not cm.transport.vehicle.cars.
Option D is incorrect because it has a typo in the keyword provides. It should be provides, not Provides. It also has a typo in the service interface name. It should be com.transport.vehicle.cars.Car, not com.transport.vehicle.cars.Car impl. It also has an unnecessary to clause, which is used to limit the accessibility of an exported package to specific modules.
Option F is incorrect because it exports the wrong package. It should export com.transport.vehicle.cars, not com.transport.vehicle.cars.impl. The impl package contains the service provider class, which should not be exposed to other modules.
Option G is incorrect because it exports the wrong package. It should export com.transport.vehicle.cars, not com.transport.vehicle. The vehicle package does not contain the service interface or the service provider class.
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Java Modules - Service Interface Module - GeeksforGeeks
Java Service Provider Interface | Baeldung
質問 # 26
Given the course table:
Given the code fragment:
- A. false
- B. 0
- C. 1
- D. true
正解：D
解説：
Explanation
The code fragment will execute the update statement and set the course fee of the course with ID 1021 to
5000. The executeUpdate method returns an int value that indicates the number of rows affected by the SQL statement. In this case, only one row will be updated, so the result variable will be 1. The if statement will check if the result is greater than 0, which is true, and print "Updated successfully". Therefore, the output of the code fragment is true. References: https://education.oracle.com/products/trackp_OCPJSE17,
https://mylearn.oracle.com/ou/learning-path/java-se-17-developer/99487,
https://docs.oracle.com/en/java/javase/17/docs/api/java.sql/java/sql/Statement.html#executeUpdate(java.lang.Str
質問 # 27
Given:
What is the result
- A. UnDefined
- B. Marketing
Finance
Technical - C. Marketing
Undefined - D. Marketing
正解：A
解説：
Explanation
The code fragment is using the switch statement with the new Java 17 syntax. The switch statement checks the value of the variable desig and executes the corresponding case statement. In this case, the value of desig is
"CTO", which does not match any of the case labels. Therefore, the default case statement is executed, which prints "Undefined". The other case statements are not executed, because there is no fall through in the new syntax. Therefore, the output of the code fragment is:
Undefined
質問 # 28
Given:
Which statement is true while the program prints GC?
- A. Only the object referenced by t2 is eligible for garbage collection.
- B. None of the objects are eligible for garbage collection.
- C. Only one of the objects previously referenced by t1 is eligible for garbage collection.
- D. Both the objects previously referenced by t1 are eligible for garbage collection.
正解：D
質問 # 29
Given:
What is the result?
- A. Nothing is printed because of an indefinite loop.
- B. A runtime exception is thrown.
- C. 0
- D. 1
- E. 2
- F. 3
- G. Compilation fails.
- H. 4
正解：G
解説：
Explanation
The code will not compile because the variable 'x' is declared as final and then it is being modified in the switch statement. This is not allowed in Java. A final variable is a variable whose value cannot be changed once it is initialized1. The switch statement tries to assign different values to 'x' depending on the value of 'y', which violates the final modifier. The compiler will report an error: The final local variable x cannot be assigned. It must be blank and not using a compound assignment. References: The final Keyword (The Java™ Tutorials > Learning the Java Language > Classes and Objects)
質問 # 30
Given:
Which two method invocation execute?
- A. IFace myclassobj = new Myc ();
myclassObj.m3 (); - B. iFace mucloassObj = new Myc ();
myClassObj.m4(); - C. new MyC() .m2 ();
- D. IFace.m2();
- E. Ifnce.m3 ();
- F. IFace .,4():
正解：C、F
解説：
The code given is an interface and a class that implements the interface. The interface has three methods, m1(), m2(), and m3(). The class has one method, m1(). The only two method invocations that will execute are D and E. D is a call to the m2() method in the class, and E is a call to the m3() method in the interface. Reference: https://education.oracle.com/products/trackp_OCPJSE17, 3, 4, 5
質問 # 31
Given:
What is the result?
- A. 1 RAINY
- B. 0 CLOUDY
- C. 1 Snowy
- D. 0 Snowy
- E. Compilation fails
正解：D
解説：
Explanation
The code is defining an enum class called Forecast with three values: SUNNY, CLOUDY, and RAINY. The toString() method is overridden to always return "SNOWY". In the main method, the ordinal value of SUNNY is printed, which is 0, followed by the value of CLOUDY converted to uppercase, which is "CLOUDY".
However, since the toString() method of Forecast returns "SNOWY" regardless of the actual value, the output will be "0 SNOWY". References: Enum (Java SE 17 & JDK 17), Enum.EnumDesc (Java SE 17 & JDK 17)
質問 # 32
Daylight Saving Time (DST) is the practice of advancing clocks at the start of spring by one hour and adjusting them backward by one hour in autumn.
Considering that in 2021, DST in Chicago (Illinois) ended on November 7th at 2 AM, and given the fragment:
What is the output?
- A. false
true - B. true
true - C. False
false - D. true
false
正解：D
解説：
Explanation
The answer is A because the code fragment uses the ZoneId and ZonedDateTime classes to create two date-time objects with the same local date-time but different zone offsets. The ZoneId class represents a time-zone ID, such as America/Chicago, and the ZonedDateTime class represents a date-time with a time-zone in the ISO-8601 calendar system. The code fragment creates two ZonedDateTime objects with the same local date-time of 2021-11-07T01:30, but different zone IDs of America/Chicago and UTC. The code fragment then compares the two objects using the equals and isEqual methods.
The equals method compares the state of two objects for equality. In this case, it compares the local date-time, zone offset, and zone ID of the two ZonedDateTime objects. Since the zone offsets and zone IDs are different, the equals method returns false.
The isEqual method compares the instant of two temporal objects for equality. In this case, it compares the instant of the two ZonedDateTime objects, which is derived from the local date-time and zone offset. Since DST in Chicago ended on November 7th at 2 AM in 2021, the local date-time of 2021-11-07T01:30 in America/Chicago corresponds to the same instant as 2021-11-07T06:30 in UTC. Therefore, the isEqual method returns true.
Hence, the output is true false. References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
ZoneId (Java Platform SE 8 )
ZonedDateTime (Java Platform SE 8 )
Time Zone & Clock Changes in Chicago, Illinois, USA
Daylight Saving Time Changes 2023 in Chicago, USA
質問 # 33
Given the code fragment:
Which code fragment returns different values?
- A. int sum = listOfNumbers. parallelStream () reduce (5, Integer:: sum) ;
- B. int sum = listOfNumbers. Stream () reduce (5, (a, b) -> a + b) ;
- C. int sum = listOfNumbers. parallelStream () reduce ({m, n) -> m +n) orElse (5) +5;
- D. int sum = listOfNumbers. Stream () reduce (0, Integer:: sum) + 5
- E. int sum = listOfNumbers. Stream () reduce ( Integer:: sum) ; +5;
正解：E
解説：
Explanation
The answer is C because the code fragment uses a different syntax and logic for the reduce operation than the other options. The reduce method in option C takes a single parameter, which is a BinaryOperator that combines two elements of the stream into one. The method returns an Optional, which may or may not contain a value depending on whether the stream is empty or not. The code fragment then adds 5 to the result of the reduce method, regardless of whether it is present or not. This may cause an exception if the Optional is empty, or produce a different value than the other options if the Optional is not empty.
The other options use a different syntax and logic for the reduce operation. They all take two parameters, which are an identity value and a BinaryOperator that combines an element of the stream with an accumulator.
The method returns the final accumulator value, which is equal to the identity value if the stream is empty, or the result of applying the BinaryOperator to all elements of the stream otherwise. The code fragments then add
5 to the result of the reduce method, which will always produce a valid value.
For example, suppose listOfNumbers contains [1, 2, 3]. Then, option A will perform the following steps:
Initialize accumulator to identity value 5
Apply BinaryOperator Integer::sum to accumulator and first element: 5 + 1 = 6 Update accumulator to 6 Apply BinaryOperator Integer::sum to accumulator and second element: 6 + 2 = 8 Update accumulator to 8 Apply BinaryOperator Integer::sum to accumulator and third element: 8 + 3 = 11 Update accumulator to 11 Return final accumulator value 11 Add 5 to final accumulator value: 11 + 5 = 16 Option B will perform the same steps as option A, except using a lambda expression instead of a method reference for the BinaryOperator. Option D will perform the same steps as option A, except using parallelStream instead of stream, which may change the order of applying the BinaryOperator but not the final result. Option E will perform the same steps as option A, except using identity value 0 instead of 5.
Option C, however, will perform the following steps:
Apply BinaryOperator Integer::sum to first and second element: 1 + 2 = 3 Apply BinaryOperator Integer::sum to previous result and third element: 3 + 3 = 6 Return Optional containing final result value 6 Add 5 to Optional value: Optional.of(6) + 5 = Optional.of(11) As you can see, option C produces a different value than the other options, and also uses a different syntax and logic for the reduce operation. References Oracle Certified Professional: Java SE 17 Developer Java SE 17 Developer OCP Oracle Certified Professional Java SE 17 Developer Study Guide Guide to Stream.reduce()
質問 # 34
Given the code fragment:
Which code fragment invokes all callable objects in the workers set?
- A.
- B.
- C.
- D.
正解：C
解説：
Explanation
The code fragment in Option C invokes all callable objects in the workers set by using the ExecutorService's invokeAll() method. This method takes a collection of Callable objects and returns a list of Future objects representing the results of the tasks. The other options are incorrect because they either use the wrong method (invokeAny() or submit()) or have syntax errors (missing parentheses or semicolons). References: AbstractExecutorService (Java SE 17 & JDK 17) - Oracle
質問 # 35
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Oracle 1Z0-829（Java SE 17 Developer）認定試験は、Java開発者のスキルと知識を検証するために設計された業界で認識された認定です。この試験は、Java開発の経験があり、Java SE 17で熟練するためのスキルを向上させたいIT専門家向けです。この試験では、ジェネリック、モジュール、ストリーム、コレクションなど、Javaプログラミングに関連するさまざまなトピックをカバーしています。
Oracle 1Z0-829：Java SE 17 Developer 試験は、Javaプログラミング言語に関する知識とスキルを評価する認定試験です。この試験は、Java SE 17を使用したアプリケーションの開発能力を測定します。プログラミング言語に強いバックグラウンドを持ち、Java SE 17での専門知識を習得したいと考えているプロフェッショナルを対象としています。
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